Category Archives: MDX

some more MDX

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Some fairly basic MDX stuff:

WITH
SET [a] AS [Geography].[City].[City] * [Product].[Category].Levels(1).Members 
SET [b] AS [Date].[Calendar].Levels(1).Members * [Sales Territory].[Sales Territory].[Country]
SELECT
     Order([a], [b].Item(0), BDESC ) ON ROWS
     ,[b]  ON COLUMNS
FROM [Adventure Works];

Use the * (asterisk) to separate multiple columns and rows. It’s a bit like a similar use in R when plotting against two things, I think the library(doBy) uses the same .

…with selection and NON EMPTY:

WITH
SET [a] AS	[Geography].[Country].&[Germany]
			*[Product].[Category].Levels(1).Members 
SET [b] AS	[Date].[Calendar].Levels(1).Members
			* [Sales Territory].[Sales Territory].[Country]
SELECT
     Order([a], [b].Item(0), BDESC ) ON ROWS
     ,non empty{[b]}  ON COLUMNS--[Geography].[City].&[Abingdon]&[ENG]
FROM [Adventure Works];

Simple MDX again

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WITH
SET [a] AS [Product].[Category].Levels(1).Members
SET [b] AS [Date].[Calendar].Levels(1).Members
SELECT
     Order([a], [b].Item(0), BDESC ) ON ROWS
     ,[b]  ON COLUMNS
FROM [Adventure Works];

The “Category” above is not an MDX keyword, but a part of the hierarchy under the “product” dimension.



What happens if you change the dimension to one in which the measure does not spread over?


WITH
SET [a] AS [Product].[Category].Levels(1).Members
SET [b] AS [Date].[Calendar].Levels(1).Members
SELECT
     Order([a], [b].Item(0), BDESC ) ON ROWS
     ,[b]  ON COLUMNS
FROM [Adventure Works];


Which gives:




 




CY 2001
CY 2002
CY 2003
CY 2004
CY 2006




Bikes
$7,395,348.63
$19,956,014.67
$25,551,775.07
$13,399,243.18
(null)




Components
$615,474.98
$3,610,092.47
$5,482,497.29
$2,091,011.92
(null)




Clothing
$34,376.34
$485,587.15
$871,864.19
$386,013.16
(null)




Accessories
$20,235.36
$92,735.35
$296,532.88
$161,794.33
(null)






Now what do we get if we only look at the top level of the row dimenion?


WITH
SET [a] AS [Product].[Category].Levels(0).Members
SET [b] AS [Date].[Calendar].Levels(1).Members
SELECT
     Order([a], [b].Item(0), BDESC ) ON ROWS
     ,[b]  ON COLUMNS
FROM [Adventure Works];




 




CY 2001
CY 2002
CY 2003
CY 2004
CY 2006




All Products
$8,065,435.31
$24,144,429.65
$32,202,669.43
$16,038,062.60
(null)






Which is just the total “whatever measure this is” for the column dimension.

Now let’s throw in a dimension which doesn’t split the measure.


WITH
SET [a] AS [Department].Levels(1).Members
SET [b] AS [Date].[Calendar].Levels(1).Members
SELECT
     Order([a], [b].Item(0), BDESC ) ON ROWS
     ,[b]  ON COLUMNS
FROM [Adventure Works];


you get this:




 




CY 2001
CY 2002
CY 2003
CY 2004
CY 2006




Executive General and Administration
$8,065,435.31
$24,144,429.65
$32,202,669.43
$16,038,062.60
(null)




Inventory Management
$8,065,435.31
$24,144,429.65
$32,202,669.43
$16,038,062.60
(null)




Manufacturing
$8,065,435.31
$24,144,429.65
$32,202,669.43
$16,038,062.60
(null)




Quality Assurance
$8,065,435.31
$24,144,429.65
$32,202,669.43
$16,038,062.60
(null)




Research and Development
$8,065,435.31
$24,144,429.65
$32,202,669.43
$16,038,062.60
(null)




Sales and Marketing
$8,065,435.31
$24,144,429.65
$32,202,669.43
$16,038,062.60
(null)






Which looks like a cartesian join enacted on a crosstab. So each example of the row dimention gets an instance of the column dimensions (which the measure is applicable to)

How do I find out how my measures and dimensions are related?

…for that you need BIDS.

					

		
		
	


				
					
	

		

						
MDX again

			
						

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WITH
SET [a] AS [Product].[Subcategory].Levels(1).Members
SET [b] AS [Date].[Calendar].Levels(1).Members
SELECT
     Order([a],[b].Item(0), BDESC ) ON ROWS,
     Order([b],[a].Item(0), BDESC  ) ON COLUMNS
FROM [Adventure Works] ;



works the same as:


WITH
SET [RowSet]    AS [Product].[Subcategory].Levels(1).Members
SET [ColumnSet] AS [Date].[Calendar].Levels(1).Members
SELECT
     Order( [RowSet], [ColumnSet].Item(0), BDESC ) ON ROWS,
     Order([ColumnSet],[RowSet].Item(0), BDESC  ) ON COLUMNS
FROM [Adventure Works];


					

		
		
	


				
					
	

		

						
A Simple MDX Example Using Adventure Works

			
						

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WITH
SET [RowSet]    AS [Product].[Subcategory].Levels(1).Members
SET [ColumnSet] AS [Product].[Category].Levels(1).Members
SELECT
     Order( [RowSet], [ColumnSet].Item(0), BDESC ) ON ROWS,
     [ColumnSet]                                   ON COLUMNS
FROM [Adventure Works]



Output(truncated):







CY 2001
CY 2002
CY 2003
CY 2004
CY 2006




Mountain Bikes
$4,545,336.51
$9,190,838.09
$8,854,263.03
$3,902,246.74
(null)




Road Bikes
$2,850,012.12
$10,765,176.58
$11,294,381.37
$4,448,636.90
(null)




Mountain Frames
$371,587.79
$1,400,331.68
$2,067,908.64
$873,844.03
(null)




Road Frames
$243,887.19
$1,618,391.51
$1,631,377.27
$356,197.37
(null)




Jerseys
$28,255.57
$110,243.77
$290,004.73
$150,804.63
(null)





If you change the value of 


     Order( [RowSet], [ColumnSet].Item(0), BDESC )



to 


     Order( [RowSet], [ColumnSet].Item(1), BDESC )



then the sorted column changes.

Also if you change the parameter of the Levels in the following section: 


SET [RowSet]    AS [Product].[Subcategory].Levels(1).Members
SET [ColumnSet] AS [Date].[Calendar].Levels(1).Members



to


SET [RowSet]    AS [Product].[Subcategory].Levels(0).Members
SET [ColumnSet] AS [Date].[Calendar].Levels(0).Members



then this collapses down to a single number so depending on how many objects exist in the dimensions hierarchy you can use higher and higher numbers for the Levels to get more columns or rows (I think). 


WITH
SET [RowSet]    AS [Product].[Subcategory].Levels(0).Members
SET [ColumnSet] AS [Date].[Calendar].Levels(1).Members
SELECT
     Order( [RowSet], [ColumnSet].Item(0), BDESC ) ON ROWS,
     Order([ColumnSet],[RowSet].Item(0), BDESC  ) ON COLUMNS
FROM [Adventure Works] ;



This now sorts by the values in the rows and columns the values used in the columns.